TI 89 Calculus > How to Find Vertical Asymptotes on the TI89
In calculus, you will be asked to find the vertical and horizontal asymptotes of a function. The vertical asymptote occurs when the denominator of a rational function is zero. You don’t have to figure out zeros for vertical asymptotes by hand: these steps show you how to find vertical asymptotes on the TI89 in seconds.
How to Find Vertical Asymptotes on the TI89: Steps
Sample problem: Find the vertical asymptotes on the TI89 for the following equation: f(x) = (x – 6) / (x2 – 8x + 12)
Note: Make sure you are on the home screen. If you aren’t on the home screen, press the Home button.
Step 1: F2 and then press 4 to select the “zeros” command.
Step 2: Press (x-6)/(x^2-8x+12),x to enter the function.
Step 3: Press ) to close the right parenthesis.
Step 4: Press Enter.
Step 5: Look at the results. The resulting zeros for this rational function will appear as a notation like: (2,6) This means that there is either a vertical asymptote or a hole at x=2 and x=6.
Step 5: Plug the values from Step 5 into the calculator to mark the difference between a vertical asymptote and a hole. The numerator is x-6, so press 2, -, -4 and then press Enter to get 6. This means that f(2) = 6, confirming there is a vertical asymptote at x=-4. When x=0, the numerator is equal to -6. This confirms that there is a hole in the graph at x=-6. If the numerator is ever equal to zero, this means that there is a hole in the graph and not a vertical asymptote.
That’s How to Find Vertical Asymptotes on the TI89!
You can double check your answer with this calculator by Symbolab.
Check out our Youtube channel for hundreds of statistics videos.
If you prefer an online interactive environment to learn R and statistics, this free R Tutorial by Datacamp is a great way to get started. If you're are somewhat comfortable with R and are interested in going deeper into Statistics, try this Statistics with R track.Comments are now closed for this post. Need help or want to post a correction? Please post a comment on our Facebook page and I'll do my best to help!