In the following figure, in ΔPQR, seg RS is the bisector of ∠PRQ. If PS = 6, SQ = 8, PR = 15, find QR.

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#### Solution

Seg RS bisects ∠PRQ ….(given)

`(PR)/(QR)= (PS)/(SQ)` ....(angle bisector property)

`15/(QR)=6/8`

`QR= (15xx8)/6=20`

Concept: Similarity of Triangles

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