Statistics Definitions > Chauvenet’s Criterion

## What is Chauvenet’s Criterion?

Chauvenet’s criterion is a way to identify outliers. The method works by creating an acceptable band of data around the mean, specifying any values that fall outside that band should be eliminated. The formula to calculate the band is:

Where n is the sample size.

Normal distribution probabilities can be used to relate the formula to a maximum deviation from the mean: **τ = |X _{i} – x̄|/ s**. This formula is a little more intuitive to use.

- The procedure should only be run once on a data set. Some authors advocate two runs; any outliers that are revealed on the second run are called
*shielded outliers*.**Note**: other authors say never to eliminate outliers, so this is a judgment call based on your data. - The procedure assumes your data is normally distributed.

## Running Chauvenet’s

You’ll probably want to perform these calculations in a spreadsheet, because the calculations can become numerous if you have multiple potential outliers (see Step 3).

For the following set of numbers, identify any outliers: 47, 50, 53, 55, 55, 56, 57, 57,58, 58, 58, 58, 60, 60, 60, 61, 61, 61, 61, 61, 61, 62, 62, 62, 63, 63, 64, 67, 68, 72.

Step 1: Calculate the sample mean, x̄. The sample mean is 59.7.

Step 2: Find the sample standard deviation, s. The sample standard deviation is 4.998.

Step 3: Use the following formula to find the standardized deviation from the mean for all suspected outliers, data values “i.”

**τ = |X _{i} – x̄|/ s**

We have thirty items in the set, so you’ll want to run the formula twenty times (one for each data point, i). For sake of brevity, I’m just going to show two of the data point calculations:

47: |47 – 59.7| / 4.998 = 2.541

67: |67 – 59.7| / 4.998 = 1.461

Step 4: Compare the values you got in Step 4 with a table of Chauvenet’s criterion values (see next section) to see if you can reject each data point. For n=30, the table tells us the band should end at 2.394 standard deviations.

47 is 2.541 standard deviations and is higher than 2.394, so should be eliminated. As 67 is under this figure, that data point stays.

If you’ve identified an abnormal amount of outliers, you might want to widen the band to include a certain percentage of data points. The empirical rule tells us that 95% of data lies within two standard deviations from the mean. Therefore a rule of thumb says that you should eliminate a maximum of 5% of your data points.

## Chauvenet’s Criterion Table

n | τ |
---|---|

3 | 1.383 |

4 | 1.534 |

5 | 1.645 |

6 | 1.732 |

7 | 1.803 |

8 | 1.863 |

9 | 1.915 |

10 | 1.960 |

11 | 2.000 |

12 | 2.037 |

13 | 2.070 |

14 | 2.100 |

15 | 2.128 |

16 | 2.154 |

17 | 2.178 |

18 | 2.200 |

19 | 2.222 |

20 | 2.241 |

21 | 2.260 |

22 | 2.278 |

23 | 2.295 |

24 | 2.311 |

25 | 2.326 |

26 | 2.341 |

27 | 2.355 |

28 | 2.369 |

29 | 2.382 |

30 | 2.394 |

31 | 2.406 |

32 | 2.418 |

33 | 2.429 |

34 | 2.440 |

35 | 2.450 |

36 | 2.460 |

37 | 2.470 |

38 | 2.479 |

39 | 2.489 |

40 | 2.498 |

50 | 2.576 |

100 | 2.807 |

500 | 3.291 |

1000 | 3.481 |

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Hello,

I am using 2*STANDARD DEVIATION while determing “T” value. Now, can I use the same Chauvenets criterion table or is there any other Chauvenet’s Table when we used 2*STANDARD DEVIATION instead of 1*STANDARD DEVIATION

Could you explain why you’re using 2*sigma instead of 1*s? I don’t know of an alternate table, but there are other outlier tests you could use.