## How do you find function intervals?

You can find the intervals of a function in two ways: with a graph, or with derivatives.

## Find function intervals using a graph

**Example Question**: Find the increasing intervals for the function g(x) = (⅓)x^{3} + 2.5x^{2} â€“ 14x + 25

Step 1: Graph the function (I used the graphing calculator at Desmos.com). This is an easy way to find function intervals. Even if you have to go a step further and “prove” where the intervals are using derivatives, it gives you a way to check your answer.

The function appears to be increasing in two intervals: (-∞, -7) and (2, ∞).

The problem with just graphing a function is **you don’t know what’s happening off the graph.** For example, you could zoom out a thousand times and never be quite sure that the graph isn’t going to do something strange, like a sudden drop. To be 100% sure of your answer, check it with the next few steps.

## Find intervals using derivatives

You can think of a derivative as the slope of a function. If the slope (or derivative) is positive, the function is increasing at that point. If it’s negative, the function is decreasing. So to find intervals of a function that are either decreasing or increasing, take the derivative and plug in a few values.

**Example Question**: Find the increasing function intervals for g(x) = (⅓)x^{3} + 2.5x^{2} â€“ 14x.

Step 1: **Find the first derivative. **For this particular function, use the power rule:

g′(x) = 3*(⅓)x^{3-1} + 2* 2.5x^{2-1} â€“ 14x^{(1-1)} + 99(0)

= x^{2} + 5x – 14

Step 2: **Set the derivative equal to zero and solve** (factoring often works):

x^{2} + 5x – 14 = 0

Factoring, we get:

(x â€“ 2)(x + 7) = 0

Solving for x gives:

x = -7, x = 2.

Step 3: **Create intervals **on the number line with the x-values from Step 3.

For this example, we have 3 intervals: (â€“∞, â€“7), (â€“7, 2), (2, ∞).

Step 4: **Pick one point in each interval to “test”**. You can choose any number in the interval, but you may want to pick a number like 0, 1, or 10 to make your calculations easier. For example, in the interval (â€“∞, â€“7), -10 is a good choice. For (â€“7, 2), let’s go with 0 and for (2, ∞), 10.

Step 5: **Plug the values you chose in Step 5 into the derivative formula **(from Step 1) to determine if the derivative has a positive or negative value. Our derivative formula is x^{2} + 5x – 14, so that gives:

- = -10
^{2}+ 5(-10) – 14 = 36 - = 0
^{2}+ 5(0) – 14 = -14 - = 10
^{2}+ 5(10) – 14 = 136

The first derivative tells us that a function is increasing when the values for the first derivative are positive. Therefore, we can conclude that the increasing function intervals are (-∞, -7) and (2, ∞).