Factoring limits is a way to find limits by canceling common factors. Usually, you’ll want to try direct substitution first. If you end up with an indeterminate limit like 0/0, try using factoring to turn the function into one where you can use substitution.
Factoring Limits Examples
Example #1: Find the limit of the following function by factoring:
Step 1: Factor the numerator, denominator, or both (this depends on what is factorable in your expression). For this example, we’re factoring the numerator, x2 – 25:
- Rewrite 25 as 52: x2 – 52: (x2 – 52)
- Apply the difference of two squares formula from algebra (x2 – y2 = (x + y)(x – y): (x + 5)(x – 5).
Step 2: Replace the factored parts of the expression back in the formula:
Step 3: Cancel like terms. For this example, we have (x – 5) in the numerator and denominator so we can cancel both of those out:
Which leaves:
Step 4: Use substitution to solve. For this example, plug 5 (the term specified by the “lim” expression) into the formula on the right (x + 5):
(5 + 5) = 10.
The limit is 10.
Example #2: Find the limit of the following function by factoring:
Step 1: Factor the numerator, denominator, or both (this depends on what is factorable in your expression). For this example, we can factor the numerator:
- Break into groups: (x2 + 3x – 4) = (x2 – x) + (4x – 4)
- Factor out x from x2 – x: x(x – 1)
- Factor out 4 from 4x – 4: 4(x – 1)
- Combine the above two expressions: x(x – 1) + 4(x – 1)
- Factor out the common term (x – 1): (x – 1)(x + 4)
Step 2: Replace the factored parts of the expression back in the formula:
Step 3: Cancel like terms.
Step 4: Use substitution to solve.
limx→-4 (x – 1) = -5.
References
7. Limits by algebraic simplification. Retrieved July 14, 2021 from: https://web.auburn.edu/holmerr/1617/Textbook/limbyalg-screen.pdf