**4/20/15 We are experiencing some issues with the site calculator below. As a temporary fix, please use the above calculator!**

Input the number of trials (n or X) into the “X” box, then type the probability into the “P(x)” box. Click “Calculate Expected Value.”

for multiple probabilities, click the “More” button to enter more X/P(X)

X

P(X)

P(X)

Sum P(x):

0

0

Expected Value:

0

0

If you prefer an online interactive environment to learn R and statistics, this free R Tutorial by Datacamp is a great way to get started. If you're are somewhat comfortable with R and are interested in going deeper into Statistics, try this Statistics with R track.

Comments are now closed for this post. Need help or want to post a correction? Please post a comment on our Facebook page and I'll do my best to help!Expected Value Calculator was last modified: October 15th, 2017 by

I typed the necessary information in multiple times ans the expected value result did not change from zero. i am very frustrated at this. take this website down if you’re going to advertise something that seems great but doesn’t work. ridiculous.

Did you hit the “calculate expected value” button? You need to do that otherwise it will stay at zero.

doesn’t work well in the slightest. i agree with andale

Hello, Paul,

It works fine for me (I tried it in IE and Chrome), so I’m stumped. If you could let me know what your inputs are I will see if I can troubleshoot.

Regards,

hi

Liam,

What trouble are you having?

Nice job with the temp. fix on the calculator, glad to see a website that genuinely is trying to help people with a format that doesn’t look like it belongs in ’02. Keep up the good work.

Thanks, Tyler. I’m constantly working to keep things updated.

first off I love the site and your videos GREAT JOB!! I told my professor about it, It is one of the reasons why I understand STATS

what calculator I use, How do I solve with a TI-84 and what video do I refer to as how to :

1. Using the tables and assuming that x is a normal (mean = 1 and standard deviation = 2), calculate

p(x>0)

p(x3)

p(x>5)

2. if x has a normal distribution with a mean 3 and standard deviation 9, calculate :

a.) p(x

b) = 0.0110I think this should help: http://www.statisticshowto.com/ti-83-normalcdf/

Glad you find the site helpful :)